Beam Overhanging One Support - Uniformly Distributed Load
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จากรูปจงเติมข้อมูลต่อไปนี้
Uniform Load : w (N/m)
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Beam long : l (m)
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ระยะที่ยื่น : a (m)
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ระยะใด ๆ : x (m)
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ระยะใด ๆ (x1 < a) : x1 (m)
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Solution
w = 0 N/m. ,
l = 0 m. ,
a = 0 m. ,
x = 0 m.
x1 = 0 m. ,
จะได้ผลลัพธ์ดังนี้
R1 = V1 =
print" ". round($R1,3); print" ";echo" N "; ?>
R2 = V2 + V3 =
print" ". round($R2,3); print" ";echo" N "; ?>
V2 =
print" ". round($V2,3); print" ";echo" N "; ?>
V3 =
print" ". round($V3,3); print" ";echo" N "; ?>
Vx (between supports) =
print" ". round($Vx,3); print" ";echo" N "; ?>
Vx1 (for overhang) =
print" ". round($Vx1,3); print" ";echo" N "; ?>
M1 (at x = ) =
print" ". round($M1,3); print" ";echo"N-m"; ?>
M2 (at R2) =
print" ". round($M2,3); print" ";echo"N-m"; ?>
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