อนุพันธ์

$y = 4 x^{3} + 5 x^{2} + 6 x + 1$

วิธีทำ

$\begin{aligned} \frac{d y}{d x} = \frac{d}{d x} (4 x^{3} + 5 x^{2} + 6 x + 1) \\ = 4 \frac{d}{d x} x^{3} + 5 \frac{d}{d x} x^{2} + 6 \frac{d}{d x} x + \frac{d}{d x} 1 \\ = 4 (3 x^{2}) + 5 (2 x) + 6 + 0 \\ = 12 x^{2} + 10 x + 6 \end{aligned}$