อนุพันธ์

$ y= \arccos (\frac{4x+5}{2+\sin x} ) $

วิธีทำ

\begin{align} & \cssId{Step1}{ \frac{dy}{dx} = - \frac{1}{\sqrt{1-(\frac{4x+5}{2+\sin x})^2} } \frac{d}{dx} (\frac{4x+5}{2+\sin x}) } \\ &\cssId{Step2}{= - \frac{1}{\sqrt{1-(\frac{4x+5}{2+\sin x})^2} } \frac{(2+\sin x) (4) - (4x+5) (\cos x) }{(2+\sin x)^2} } \\ \end{align}